X^2+2x-25,6=0

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Solution for X^2+2x-25,6=0 equation: 



X^2+2X-25.6=0

a = 1; b = 2; c = -25.6;
Δ = b2-4ac
Δ = 22-4·1·(-25.6)
Δ = 106.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{106.4}}{2*1}=\frac{-2-\sqrt{106.4}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{106.4}}{2*1}=\frac{-2+\sqrt{106.4}}{2}
$

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